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已知函数F(x)=Cos(2x+ π/3)+ sin^2 x

f(x)=sin(x+x+π/3)-sin(-π/3)-√3/2(1+cos2x)+1/2sin2x

h(x)=f(x)+g(x)=cos²x+π/12+1+1/2sin2x =

f(x)=[2sin(x+π/3)+sinx]cosx -√3sin²x =[2

f(x)=(2+sin²x)/sin2x f'(x)=[sin2xsi

解: f(x)=sin²x+√3sinxcosx+2cos²x

f(x)=2sinxcosx+2√3sin²x-√3 =2sinxco

已知函数f(x)=2sinxcosx-2(√3)cos²x+√3;求f(x)的单调

【公式】: ① sina * cosb + cosa * sinb = si

f(x)=根号3sinx(cosxcosPai/3-sinxsinPai&#

用倍角公式:COS(2A)=1-2*(SIN(A))^2.

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